PickledHero

11051 pts ยท December 27, 2013


Got pickles?

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8 years ago | Likes 2 Dislikes 0

I vow not to repost anymore, each pickle I post, will be slightly more zoomed in than the last

9 years ago | Likes 2 Dislikes 3

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9 years ago | Likes 1 Dislikes 1

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9 years ago | Likes 1 Dislikes 1

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9 years ago | Likes 1 Dislikes 1

sex or nah?

9 years ago | Likes 3 Dislikes 1

As an overweight ginger man, we all are, all the time.

9 years ago | Likes 11 Dislikes 0

@ImAHeckingMerman

9 years ago | Likes 2 Dislikes 0

Sweet, thanks, more books for my to read list.

9 years ago | Likes 2 Dislikes 0

You seem to have good taste, if you make another one of these, tag me please.

9 years ago | Likes 3 Dislikes 0

In which case you press next until you've seen the episode.

9 years ago | Likes 3 Dislikes 0

connect a 100Mohm resistor, it would require 100kV

10 years ago | Likes 1 Dislikes 0

heavily dependent on the circuit, connect any resistor across 2 battery terminals and it's still at X volts, but for say a 1mA source, if we

10 years ago | Likes 1 Dislikes 0

Also when dealing with electrical equipment in labs, it's far more common to have a voltage source than a current source as current is

10 years ago | Likes 1 Dislikes 0

http://carbatteryonline.net/car-battery-tester.html for car battery, obviously other types of batteries have different life spans

10 years ago | Likes 1 Dislikes 0

A resistor can only dissipate power as heat,other sources like an LED or motor dissipate power as light or rotation in combination with heat

10 years ago | Likes 1 Dislikes 0

The circuit above is pretty efficient, it's designed to create a hot cutting element, a low resistance wire does this.

10 years ago | Likes 1 Dislikes 0

With a 12 volt battery,a full charge is considered 12.6V,while a dead battery is considered 11.9V, within 5% of 12V~constant. Also AC mains.

10 years ago | Likes 1 Dislikes 0

We generally deal with constant voltage sources ie, batteries

10 years ago | Likes 1 Dislikes 0

and voltage across of the battery.

10 years ago | Likes 1 Dislikes 0

For instance, in a battery the power generated by the battery is also IV where I and V are the current through

10 years ago | Likes 1 Dislikes 0

where I is the current through the resistor. This relation P=IV is correct for any component

10 years ago | Likes 1 Dislikes 0

P=delta(qV)/delta(t)=IV

10 years ago | Likes 1 Dislikes 0

when it hits the ground. We refer to this conversion of potential energy into heat as dissipation

10 years ago | Likes 1 Dislikes 0

This energy goes into heat, much like the way a ball of putty that falls off a cliff converts its potential energy to heat

10 years ago | Likes 1 Dislikes 0

As a charge q moves through a resistor, it loses a potential energy qV where V is the potential drop across the resistor.

10 years ago | Likes 1 Dislikes 0

A low R creates a large I, this creates more heat.

10 years ago | Likes 1 Dislikes 0

Heat generated by resistance is proportional to the resistance and the current squared* Current has a much larger impact on the heat than R

10 years ago | Likes 1 Dislikes 0

from your own site ((y))

10 years ago | Likes 1 Dislikes 0